Invert a binary tree.
4
/ \
2 7
/ \ / \
1 3 6 9
to
4
/ \
7 2
/ \ / \
9 6 3 1
Trivia:
This problem was inspired by this original tweet by Max Howell:
Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.
这是一个有趣的故事,Homebrew的作者Max Howell去Google面试,有一道面试题是在白板上写反转二叉树,Max Howell没写出来,被拒掉了。Max Howell回来后就在推特上发帖:"Google: 虽然我们(Google工程师)有90%都在用你写的软件,但你不能在白板上写反转二叉树,所以快滚吧!!"
递归交换左右子树即可。
代码
class Solution {
public:
TreeNode* invertTree(TreeNode* root) {
if(root==0) return 0;
TreeNode* p = root->right;
root->right = root->left;
root->left = p;
invertTree(root->right);
invertTree(root->left);
return root;
}
};