问题描述
Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.
分析
直接将下一个节点的值赋值给当前节点,然后将当前节点的下一个节点设置为下一个节点的下一个节点既可。
代码
void deleteNode(ListNode* node) {
if(node==0) return;
if(node->next==0) return;
node->val = node->next->val;
node->next = node->next->next;
}